Integrand size = 35, antiderivative size = 694 \[ \int \frac {\sqrt {a+b x^3} \left (c+d x+e x^2+f x^3+g x^4\right )}{x^5} \, dx=\frac {3 c \sqrt {a+b x^3}}{20 x^4}+\frac {d \sqrt {a+b x^3}}{3 x^3}+\frac {3 e \sqrt {a+b x^3}}{2 x^2}-\frac {3 (b c+8 a f) \sqrt {a+b x^3}}{8 a x}+\frac {3 \sqrt [3]{b} (b c+8 a f) \sqrt {a+b x^3}}{8 a \left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )}-\frac {2 \sqrt {a+b x^3} \left (3 c x+5 d x^2+15 e x^3-15 f x^4-5 g x^5\right )}{15 x^5}-\frac {(b d+2 a g) \text {arctanh}\left (\frac {\sqrt {a+b x^3}}{\sqrt {a}}\right )}{3 \sqrt {a}}-\frac {3 \sqrt [4]{3} \sqrt {2-\sqrt {3}} \sqrt [3]{b} (b c+8 a f) \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} E\left (\arcsin \left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}{\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}\right )|-7-4 \sqrt {3}\right )}{16 a^{2/3} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}+\frac {3^{3/4} \sqrt {2+\sqrt {3}} \sqrt [3]{b} \left (4 a^{2/3} \sqrt [3]{b} e-\left (1-\sqrt {3}\right ) (b c+8 a f)\right ) \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}{\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}\right ),-7-4 \sqrt {3}\right )}{8 a^{2/3} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}} \]
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Time = 0.71 (sec) , antiderivative size = 694, normalized size of antiderivative = 1.00, number of steps used = 12, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.257, Rules used = {1840, 1849, 1846, 272, 65, 214, 1892, 224, 1891} \[ \int \frac {\sqrt {a+b x^3} \left (c+d x+e x^2+f x^3+g x^4\right )}{x^5} \, dx=\frac {3^{3/4} \sqrt {2+\sqrt {3}} \sqrt [3]{b} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt [3]{b} x+\left (1-\sqrt {3}\right ) \sqrt [3]{a}}{\sqrt [3]{b} x+\left (1+\sqrt {3}\right ) \sqrt [3]{a}}\right ),-7-4 \sqrt {3}\right ) \left (4 a^{2/3} \sqrt [3]{b} e-\left (1-\sqrt {3}\right ) (8 a f+b c)\right )}{8 a^{2/3} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}-\frac {3 \sqrt [4]{3} \sqrt {2-\sqrt {3}} \sqrt [3]{b} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} (8 a f+b c) E\left (\arcsin \left (\frac {\sqrt [3]{b} x+\left (1-\sqrt {3}\right ) \sqrt [3]{a}}{\sqrt [3]{b} x+\left (1+\sqrt {3}\right ) \sqrt [3]{a}}\right )|-7-4 \sqrt {3}\right )}{16 a^{2/3} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}-\frac {\text {arctanh}\left (\frac {\sqrt {a+b x^3}}{\sqrt {a}}\right ) (2 a g+b d)}{3 \sqrt {a}}-\frac {2 \sqrt {a+b x^3} \left (3 c x+5 d x^2+15 e x^3-15 f x^4-5 g x^5\right )}{15 x^5}-\frac {3 \sqrt {a+b x^3} (8 a f+b c)}{8 a x}+\frac {3 \sqrt [3]{b} \sqrt {a+b x^3} (8 a f+b c)}{8 a \left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )}+\frac {3 c \sqrt {a+b x^3}}{20 x^4}+\frac {d \sqrt {a+b x^3}}{3 x^3}+\frac {3 e \sqrt {a+b x^3}}{2 x^2} \]
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Rule 65
Rule 214
Rule 224
Rule 272
Rule 1840
Rule 1846
Rule 1849
Rule 1891
Rule 1892
Rubi steps \begin{align*} \text {integral}& = -\frac {2 \sqrt {a+b x^3} \left (3 c x+5 d x^2+15 e x^3-15 f x^4-5 g x^5\right )}{15 x^5}+\frac {1}{2} (3 a) \int \frac {-\frac {2 c}{5}-\frac {2 d x}{3}-2 e x^2+2 f x^3+\frac {2 g x^4}{3}}{x^5 \sqrt {a+b x^3}} \, dx \\ & = \frac {3 c \sqrt {a+b x^3}}{20 x^4}-\frac {2 \sqrt {a+b x^3} \left (3 c x+5 d x^2+15 e x^3-15 f x^4-5 g x^5\right )}{15 x^5}-\frac {3}{16} \int \frac {\frac {16 a d}{3}+16 a e x-2 (b c+8 a f) x^2-\frac {16}{3} a g x^3}{x^4 \sqrt {a+b x^3}} \, dx \\ & = \frac {3 c \sqrt {a+b x^3}}{20 x^4}+\frac {d \sqrt {a+b x^3}}{3 x^3}-\frac {2 \sqrt {a+b x^3} \left (3 c x+5 d x^2+15 e x^3-15 f x^4-5 g x^5\right )}{15 x^5}+\frac {\int \frac {-96 a^2 e+12 a (b c+8 a f) x+16 a (b d+2 a g) x^2}{x^3 \sqrt {a+b x^3}} \, dx}{32 a} \\ & = \frac {3 c \sqrt {a+b x^3}}{20 x^4}+\frac {d \sqrt {a+b x^3}}{3 x^3}+\frac {3 e \sqrt {a+b x^3}}{2 x^2}-\frac {2 \sqrt {a+b x^3} \left (3 c x+5 d x^2+15 e x^3-15 f x^4-5 g x^5\right )}{15 x^5}-\frac {\int \frac {-48 a^2 (b c+8 a f)-64 a^2 (b d+2 a g) x-96 a^2 b e x^2}{x^2 \sqrt {a+b x^3}} \, dx}{128 a^2} \\ & = \frac {3 c \sqrt {a+b x^3}}{20 x^4}+\frac {d \sqrt {a+b x^3}}{3 x^3}+\frac {3 e \sqrt {a+b x^3}}{2 x^2}-\frac {3 (b c+8 a f) \sqrt {a+b x^3}}{8 a x}-\frac {2 \sqrt {a+b x^3} \left (3 c x+5 d x^2+15 e x^3-15 f x^4-5 g x^5\right )}{15 x^5}+\frac {\int \frac {128 a^3 (b d+2 a g)+192 a^3 b e x+48 a^2 b (b c+8 a f) x^2}{x \sqrt {a+b x^3}} \, dx}{256 a^3} \\ & = \frac {3 c \sqrt {a+b x^3}}{20 x^4}+\frac {d \sqrt {a+b x^3}}{3 x^3}+\frac {3 e \sqrt {a+b x^3}}{2 x^2}-\frac {3 (b c+8 a f) \sqrt {a+b x^3}}{8 a x}-\frac {2 \sqrt {a+b x^3} \left (3 c x+5 d x^2+15 e x^3-15 f x^4-5 g x^5\right )}{15 x^5}+\frac {\int \frac {192 a^3 b e+48 a^2 b (b c+8 a f) x}{\sqrt {a+b x^3}} \, dx}{256 a^3}+\frac {1}{2} (b d+2 a g) \int \frac {1}{x \sqrt {a+b x^3}} \, dx \\ & = \frac {3 c \sqrt {a+b x^3}}{20 x^4}+\frac {d \sqrt {a+b x^3}}{3 x^3}+\frac {3 e \sqrt {a+b x^3}}{2 x^2}-\frac {3 (b c+8 a f) \sqrt {a+b x^3}}{8 a x}-\frac {2 \sqrt {a+b x^3} \left (3 c x+5 d x^2+15 e x^3-15 f x^4-5 g x^5\right )}{15 x^5}+\frac {\left (3 b^{2/3} (b c+8 a f)\right ) \int \frac {\left (1-\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}{\sqrt {a+b x^3}} \, dx}{16 a}+\frac {1}{16} \left (3 b^{2/3} \left (4 \sqrt [3]{b} e-\frac {\left (1-\sqrt {3}\right ) (b c+8 a f)}{a^{2/3}}\right )\right ) \int \frac {1}{\sqrt {a+b x^3}} \, dx+\frac {1}{6} (b d+2 a g) \text {Subst}\left (\int \frac {1}{x \sqrt {a+b x}} \, dx,x,x^3\right ) \\ & = \frac {3 c \sqrt {a+b x^3}}{20 x^4}+\frac {d \sqrt {a+b x^3}}{3 x^3}+\frac {3 e \sqrt {a+b x^3}}{2 x^2}-\frac {3 (b c+8 a f) \sqrt {a+b x^3}}{8 a x}+\frac {3 \sqrt [3]{b} (b c+8 a f) \sqrt {a+b x^3}}{8 a \left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )}-\frac {2 \sqrt {a+b x^3} \left (3 c x+5 d x^2+15 e x^3-15 f x^4-5 g x^5\right )}{15 x^5}-\frac {3 \sqrt [4]{3} \sqrt {2-\sqrt {3}} \sqrt [3]{b} (b c+8 a f) \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} E\left (\sin ^{-1}\left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}{\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}\right )|-7-4 \sqrt {3}\right )}{16 a^{2/3} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}+\frac {3^{3/4} \sqrt {2+\sqrt {3}} \sqrt [3]{b} \left (4 \sqrt [3]{b} e-\frac {\left (1-\sqrt {3}\right ) (b c+8 a f)}{a^{2/3}}\right ) \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} F\left (\sin ^{-1}\left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}{\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}\right )|-7-4 \sqrt {3}\right )}{8 \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}+\frac {(b d+2 a g) \text {Subst}\left (\int \frac {1}{-\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {a+b x^3}\right )}{3 b} \\ & = \frac {3 c \sqrt {a+b x^3}}{20 x^4}+\frac {d \sqrt {a+b x^3}}{3 x^3}+\frac {3 e \sqrt {a+b x^3}}{2 x^2}-\frac {3 (b c+8 a f) \sqrt {a+b x^3}}{8 a x}+\frac {3 \sqrt [3]{b} (b c+8 a f) \sqrt {a+b x^3}}{8 a \left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )}-\frac {2 \sqrt {a+b x^3} \left (3 c x+5 d x^2+15 e x^3-15 f x^4-5 g x^5\right )}{15 x^5}-\frac {(b d+2 a g) \tanh ^{-1}\left (\frac {\sqrt {a+b x^3}}{\sqrt {a}}\right )}{3 \sqrt {a}}-\frac {3 \sqrt [4]{3} \sqrt {2-\sqrt {3}} \sqrt [3]{b} (b c+8 a f) \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} E\left (\sin ^{-1}\left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}{\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}\right )|-7-4 \sqrt {3}\right )}{16 a^{2/3} \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}}+\frac {3^{3/4} \sqrt {2+\sqrt {3}} \sqrt [3]{b} \left (4 \sqrt [3]{b} e-\frac {\left (1-\sqrt {3}\right ) (b c+8 a f)}{a^{2/3}}\right ) \left (\sqrt [3]{a}+\sqrt [3]{b} x\right ) \sqrt {\frac {a^{2/3}-\sqrt [3]{a} \sqrt [3]{b} x+b^{2/3} x^2}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} F\left (\sin ^{-1}\left (\frac {\left (1-\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}{\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x}\right )|-7-4 \sqrt {3}\right )}{8 \sqrt {\frac {\sqrt [3]{a} \left (\sqrt [3]{a}+\sqrt [3]{b} x\right )}{\left (\left (1+\sqrt {3}\right ) \sqrt [3]{a}+\sqrt [3]{b} x\right )^2}} \sqrt {a+b x^3}} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 10.45 (sec) , antiderivative size = 238, normalized size of antiderivative = 0.34 \[ \int \frac {\sqrt {a+b x^3} \left (c+d x+e x^2+f x^3+g x^4\right )}{x^5} \, dx=-\frac {4 a d x+4 b d x^4-8 a g x^4-8 b g x^7+8 \sqrt {a} g x^4 \sqrt {a+b x^3} \text {arctanh}\left (\frac {\sqrt {a+b x^3}}{\sqrt {a}}\right )+4 b d x^4 \sqrt {1+\frac {b x^3}{a}} \text {arctanh}\left (\sqrt {1+\frac {b x^3}{a}}\right )+3 a c \sqrt {1+\frac {b x^3}{a}} \operatorname {Hypergeometric2F1}\left (-\frac {4}{3},-\frac {1}{2},-\frac {1}{3},-\frac {b x^3}{a}\right )+6 a e x^2 \sqrt {1+\frac {b x^3}{a}} \operatorname {Hypergeometric2F1}\left (-\frac {2}{3},-\frac {1}{2},\frac {1}{3},-\frac {b x^3}{a}\right )+12 a f x^3 \sqrt {1+\frac {b x^3}{a}} \operatorname {Hypergeometric2F1}\left (-\frac {1}{2},-\frac {1}{3},\frac {2}{3},-\frac {b x^3}{a}\right )}{12 x^4 \sqrt {a+b x^3}} \]
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Time = 1.78 (sec) , antiderivative size = 845, normalized size of antiderivative = 1.22
method | result | size |
elliptic | \(\text {Expression too large to display}\) | \(845\) |
risch | \(\text {Expression too large to display}\) | \(1243\) |
default | \(\text {Expression too large to display}\) | \(1286\) |
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.64 (sec) , antiderivative size = 330, normalized size of antiderivative = 0.48 \[ \int \frac {\sqrt {a+b x^3} \left (c+d x+e x^2+f x^3+g x^4\right )}{x^5} \, dx=\left [\frac {36 \, a \sqrt {b} e x^{4} {\rm weierstrassPInverse}\left (0, -\frac {4 \, a}{b}, x\right ) + 2 \, {\left (b d + 2 \, a g\right )} \sqrt {a} x^{4} \log \left (-\frac {b^{2} x^{6} + 8 \, a b x^{3} - 4 \, {\left (b x^{3} + 2 \, a\right )} \sqrt {b x^{3} + a} \sqrt {a} + 8 \, a^{2}}{x^{6}}\right ) - 9 \, {\left (b c + 8 \, a f\right )} \sqrt {b} x^{4} {\rm weierstrassZeta}\left (0, -\frac {4 \, a}{b}, {\rm weierstrassPInverse}\left (0, -\frac {4 \, a}{b}, x\right )\right ) + {\left (16 \, a g x^{4} - 12 \, a e x^{2} - 3 \, {\left (3 \, b c + 8 \, a f\right )} x^{3} - 8 \, a d x - 6 \, a c\right )} \sqrt {b x^{3} + a}}{24 \, a x^{4}}, \frac {36 \, a \sqrt {b} e x^{4} {\rm weierstrassPInverse}\left (0, -\frac {4 \, a}{b}, x\right ) + 4 \, {\left (b d + 2 \, a g\right )} \sqrt {-a} x^{4} \arctan \left (\frac {2 \, \sqrt {b x^{3} + a} \sqrt {-a}}{b x^{3} + 2 \, a}\right ) - 9 \, {\left (b c + 8 \, a f\right )} \sqrt {b} x^{4} {\rm weierstrassZeta}\left (0, -\frac {4 \, a}{b}, {\rm weierstrassPInverse}\left (0, -\frac {4 \, a}{b}, x\right )\right ) + {\left (16 \, a g x^{4} - 12 \, a e x^{2} - 3 \, {\left (3 \, b c + 8 \, a f\right )} x^{3} - 8 \, a d x - 6 \, a c\right )} \sqrt {b x^{3} + a}}{24 \, a x^{4}}\right ] \]
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Time = 3.61 (sec) , antiderivative size = 274, normalized size of antiderivative = 0.39 \[ \int \frac {\sqrt {a+b x^3} \left (c+d x+e x^2+f x^3+g x^4\right )}{x^5} \, dx=\frac {\sqrt {a} c \Gamma \left (- \frac {4}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {4}{3}, - \frac {1}{2} \\ - \frac {1}{3} \end {matrix}\middle | {\frac {b x^{3} e^{i \pi }}{a}} \right )}}{3 x^{4} \Gamma \left (- \frac {1}{3}\right )} + \frac {\sqrt {a} e \Gamma \left (- \frac {2}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {2}{3}, - \frac {1}{2} \\ \frac {1}{3} \end {matrix}\middle | {\frac {b x^{3} e^{i \pi }}{a}} \right )}}{3 x^{2} \Gamma \left (\frac {1}{3}\right )} + \frac {\sqrt {a} f \Gamma \left (- \frac {1}{3}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, - \frac {1}{3} \\ \frac {2}{3} \end {matrix}\middle | {\frac {b x^{3} e^{i \pi }}{a}} \right )}}{3 x \Gamma \left (\frac {2}{3}\right )} - \frac {2 \sqrt {a} g \operatorname {asinh}{\left (\frac {\sqrt {a}}{\sqrt {b} x^{\frac {3}{2}}} \right )}}{3} + \frac {2 a g}{3 \sqrt {b} x^{\frac {3}{2}} \sqrt {\frac {a}{b x^{3}} + 1}} - \frac {\sqrt {b} d \sqrt {\frac {a}{b x^{3}} + 1}}{3 x^{\frac {3}{2}}} + \frac {2 \sqrt {b} g x^{\frac {3}{2}}}{3 \sqrt {\frac {a}{b x^{3}} + 1}} - \frac {b d \operatorname {asinh}{\left (\frac {\sqrt {a}}{\sqrt {b} x^{\frac {3}{2}}} \right )}}{3 \sqrt {a}} \]
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\[ \int \frac {\sqrt {a+b x^3} \left (c+d x+e x^2+f x^3+g x^4\right )}{x^5} \, dx=\int { \frac {{\left (g x^{4} + f x^{3} + e x^{2} + d x + c\right )} \sqrt {b x^{3} + a}}{x^{5}} \,d x } \]
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\[ \int \frac {\sqrt {a+b x^3} \left (c+d x+e x^2+f x^3+g x^4\right )}{x^5} \, dx=\int { \frac {{\left (g x^{4} + f x^{3} + e x^{2} + d x + c\right )} \sqrt {b x^{3} + a}}{x^{5}} \,d x } \]
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Timed out. \[ \int \frac {\sqrt {a+b x^3} \left (c+d x+e x^2+f x^3+g x^4\right )}{x^5} \, dx=\int \frac {\sqrt {b\,x^3+a}\,\left (g\,x^4+f\,x^3+e\,x^2+d\,x+c\right )}{x^5} \,d x \]
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